Proof that 1=2

Assume x = 1 and y = 1.
Then

  • obviously:
  • x = y

  • now, multiply both sides by x:
  • x^2 = xy

  • now, subtract y2 from both sides:
  • x^2 - y^2 = xy - y^2

  • now, factorize:
  • (x+y)(x - y)=y(x - y)

  • now, cancel (x-y) term:
  • (x + y) = y

  • Therefore,
  • 2 = 1

    QED.

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    2 responses to “Proof that 1=2

    1. Err… when you ‘cancel (x-y) term’ you’re really dividing both sides of the equation by (x-y); i.e. dividing both sides by zero. As a coder I’m sure you know this 🙂 . I prefer the ‘proof’ that 0=1 – a less obviously flawed argument.

      (Found your blog after reading Ian Wishart’s Wikipedia page and noticing you too live in Chch!)

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